SOLUTION: Please help me solve this problem. I have tried, but it seems like something is missing. Rosa drives to Barnesville at 50 mph and returns by a road 5 miles longer at 40 mph. T

Question 22802: Please help me solve this problem. I have tried, but it seems like something is missing.
Rosa drives to Barnesville at 50 mph and returns by a road 5 miles longer at 40 mph. The return trip takes 15 minutes longer. How long is each road?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Distance = (rate in mph)(time in hrs.)
Data going to Barnesville:
Let distance = d; rate is 50mph; time is t
Data returning:
distance = d+5; rate is 40mph; time is (t+(1/4)
Equations
To Barnesville: d = 50t
From Barnesville: d+5 =40(t+(1/4))
Solve by substitution:
50t + 5 = 40t+10
10t = 5
t = 1/2
Solve for distance:
To Barnes: d = 50t = 50(1/2) = 25 miles
From Barnes: d+5 = 20 miles
Cheers,
Stan H.

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