SOLUTION: An airplane flew with the wind for 5 hours. The return trip against the wind took 6 hours. If the wind was blowing at 25mph. What was the rate of the plane in still the air?
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Question 227725: An airplane flew with the wind for 5 hours. The return trip against the wind took 6 hours. If the wind was blowing at 25mph. What was the rate of the plane in still the air?
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
An airplane flew with the wind for 5 hours. The return trip against the wind took 6 hours. If the wind was blowing at 25mph. What was the rate of the plane in still the air?
Step 1. distance= speed * time
Step 2. Let x+25 be the airplane speed with the wind.
Step 3. Let x-25 be the airplane speed against the wind.
Step 4. Let 5(x+25) be the distance traveled with the wind after 5 hours.
Step 5. Let 6(x-25) be the distance traveled again the wind after 6 hours.
Step 6. Equate Steps 4 and 5 since the distances are the same.
Add 150-5x to both sides of the equation
Check if distances are equal: (275+25)5=(275-25)6 which is a true statement.
Step 7. ANSWER: The speed of the plane is 275 miles per hour.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
http://www.FreedomUniversity.TV
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