SOLUTION: A football is kicked vertically upward from a height of 2 feet with an initial speed of 50 feet per second. The formula h=2+50t-16t^2 describes the ball's height above ground. h,
Algebra.Com
Question 227583: A football is kicked vertically upward from a height of 2 feet with an initial speed of 50 feet per second. The formula h=2+50t-16t^2 describes the ball's height above ground. h, in feet, t in seconds after it was kicked. What was the ball's height 2 seconds after it was kicked?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h=2+50t-16t^2
At t = 2: h = 2 + 100 - 64
h(2) = 38 feet
RELATED QUESTIONS
Please help me solve: a football is kicked vertically upward from a height of 2 feet with (answered by ikleyn)
A football is kicked vertically upward from a height of 4 feet with an initial speed of... (answered by rapaljer)
A football is kicked straight up from a height of 4 feet with an initial speed of 50 feet (answered by ankor@dixie-net.com)
A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
Quinn punted the football from a height of 3 feet above the turf field.The ball was... (answered by Alan3354)
"a football player punts a football at an inclination of 45 degrees to the horizontal at... (answered by rothauserc)
A football is punted from a height of 2.5 feet above the ground with an initial vertical... (answered by ankor@dixie-net.com)
The formula h=vt-16^2 models a football being kicked into the air where h is the height... (answered by solver91311)