SOLUTION: what is the equation for this. at 10 a.m. a car leaves a house at a rate of 60 miles perhour at the same time another car leaves the same house at a rate of50 miles per hour in the

SOLUTION: what is the equation for this. at 10 a.m. a car leaves a house at a rate of 60 miles perhour at the same time another car leaves the same house at a rate of50 miles per hour in the

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Question 221436: what is the equation for this. at 10 a.m. a car leaves a house at a rate of 60 miles perhour at the same time another car leaves the same house at a rate of50 miles per hour in the the opposite direction at what time will the cars ve 330 miles apart
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
60t+50t=330
110t=330
t=330/110
t=3 hours they will be 330 miles apart.
Proof:
60*3+50*3=330
180+150=330
330=330
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