SOLUTION: My question is a precalculus question and it wants us to basically translate word problem into a function
Car A passes point O heading east at a constant rate of 40mi/h; car B p
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Car A passes point O heading east at a constant rate of 40mi/h; car B p
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Question 215507This question is from textbook
: My question is a precalculus question and it wants us to basically translate word problem into a function
Car A passes point O heading east at a constant rate of 40mi/h; car B passes the same point 1 hour later heading north at a constant rate of 60mi/h. Express the distance between the cars as a function of time t, where t is measured starting when car B passes point O.
I drew a diagram of this, and thought of using the Pythagorean Theorum to find the distance between car A and Car b, but I just don't know how to incoporate the "1 hour later part." the answer in the book is 20 This question is from textbook
You can put this solution on YOUR website! Car A passes point O heading east at a constant rate of 40mi/h; car B passes the same point 1 hour later heading north at a constant rate of 60mi/h.
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Car A DATA:
rate = 40 mph ; time = t+1 hrs ; distance = rt = 40(t+1) miles
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Car B DATA:
rate = 60 mph ; time = t hrs ; distance = 60t miles
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Express the distance between the cars as a function of time t, where t is measured starting when car B passes point O.
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Yes, use the Pythagorean Equation to get:
(distance between A and B) = sqrt[(60t)^2 + (40(t+1))^2]
d = 3600t^2 + 1600(t^2+2t+1)
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Cheers,
Stan H.
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