SOLUTION: Jim leaves work at 6am going 60mph. Pat leaves at 7am going 78mph. How long till they are at the same point?

Question 209035: Jim leaves work at 6am going 60mph. Pat leaves at 7am going 78mph. How long till they are at the same point?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Jim leaves work at 6am going 60 mph.
Pat leaves at 7am going 78 mph.
How long till they are at the same point?
;
Let t = travel time of Jim
then
(t-1) = Pat's travel time
:
When P and J are at the same point, they will have traveled the same distance.
Write a distance equation. Dist = speed * time
:
P's dist = J's dist
78(t-1) = 60t
:
78t - 78 = 60t
:
78t - 60t = 78
:
18t = 78
t =
t = 4 hrs, that's 4 hr, 20 min
:
They will be at the same point at 10:20 AM
;
;
Check solution; find the distances
60 * 4.33 ~ 260 mi
78 * 3.33 ~ 260 mi

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