SOLUTION: Raffaele ran 8 miles and then walked 6 miles. If he ran 5 mph faster than he walked and the total time was 2 hours, then how fast did he walk?

Question 207393This question is from textbook Elementary and Intermediate Algebra
: Raffaele ran 8 miles and then walked 6 miles. If he ran 5 mph faster than he walked and the total time was 2 hours, then how fast did he walk? This question is from textbook Elementary and Intermediate Algebra

Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
For the 8 miles running:

For the 6 miles walking:

given:

---------------------

and

therefore

substituting:

solve using quadratic formula

hrs

hrs

His rate walking was 5 mi/hr
check answer:

OK

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Raffaele ran 8 miles and then walked 6 miles. If he ran 5 mph faster than he walked and the total time was 2 hours, then how fast did he walk?

Let Raffaele's walking rate of speed be S

Then his running rate of speed is S + 5 (he ran 5 mph faster than he walked)

Since he ran 8 miles, walked 6 miles, and did them in 2 hours, then

8(S) + 6(S + 5) = 2(S)(S + 5) [Multiplying equation by LCD, S(S + 5)]

Eliminate 2 = 0, as

(S - 5)(S + 3) = 0

S = 5, or - 3 (Eliminate S = -3, as rate of speed CANNOT be negative)

Therefore, Raffaele's walking rate of speed = mph

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