SOLUTION: After being shot into the air, the height of a rocket is h=80t-16t^2 where h is the height above the ground, in feet, after t seconds. After how many seconds will the rocket be at

Question 205040: After being shot into the air, the height of a rocket is h=80t-16t^2 where h is the height above the ground, in feet, after t seconds. After how many seconds will the rocket be at a height of 96 feet?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
After being shot into the air, the height of a rocket is h=80t-16t^2 where h is the height above the ground, in feet, after t seconds. After how many seconds will the rocket be at a height of 96 feet?
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96 = 80t - 16t^2
t^2 - 5t + 6 = 0
(t-2)*(t-3) = 0
t = 2 going up
t = 3 going down
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