SOLUTION: With a tail wind, a plane traveled 300 mi in 5 hours. With a head wind, the plane traveled the same distance in 8 hours. Which system of equations could be used to solve this probl

Question 204027This question is from textbook
: With a tail wind, a plane traveled 300 mi in 5 hours. With a head wind, the plane traveled the same distance in 8 hours. Which system of equations could be used to solve this problem? (Let s be the speed of the plane and w be the tailwind.) This question is from textbook

Found 2 solutions by scott8148, RAY100:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
d = r * t

(s + w) * 5 = 300

(s - w) * 8 = 300
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
velocity = distance / Time,,,,or t=d/v
.
d/v1 = 5,,,,,300/(s+w) =5,,,,300=5(s+w) = 5s +5w
.
d/v2 = 8,,,,,300/(s-w) =8,,,,,300 = 8(s-w) = 8s-8w
.
multiply first by 8,,,and 2nd by 5
,
2400=40s +40w
1500=40s-40w
.
adding together
.
3900 = 80s
.
48.75 = s
.
substituting in first eqn ,,,300 =5(48.75) +5w,,,,w=11.25
.
checking, 300/ (48.75 +11.25) = 5,,,ok
300/(48.75-11.25) = 8,,,ok

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