SOLUTION: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a fo

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Question 203746: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 36 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curce of radius 570 feet at 50 mph?
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
First write the formula:
where:
F = The required force, k = the constant of proportionality, W = car's weight in lbs, S = the speed of the car, in mph., and R = the radius of curvature in feet
To find k, make the appropriate substitutions of the given parameters:
F = 36 lbs.
W = 1800 lbs.
S = 20 mph.
R = 600 feet.
Multiply both sides by 600.

Divide both sides by 720000.

Now the formula is:
Substitute: W=1800lbs, S = 50mph, and R = 570 feet.
Evaluate.

lbs.
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