SOLUTION: while waiting for a train, bong takes a bus ride at 60 kph to a certain point and then walks back leisurely at 10 kph. The bus takes 15 minutes less than his walking. how far has h

Question 202364: while waiting for a train, bong takes a bus ride at 60 kph to a certain point and then walks back leisurely at 10 kph. The bus takes 15 minutes less than his walking. how far has he walked and for how long?
this what i did:
d=60(15-t)
d=10t
d=900-60t
60t+10t=900-60t i transposed the 60t
70t=900 and i divide both sides by 70 but i cant get the answer for the 900
Please if you can even include how to get the answer thanks in advance
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
You're on the right track, but have an error in the logic used to represent the bus ride time
Let t be the time it takes to walk in hours. Then bus ride time is (remember your time needs to be in the same units. So we have to convert 15 minutes into hours)
You know that
And you also know the distance is the same in both directions.
So

<--- this is where your error in bustime messed you up

hours
That's 18 minutes.
If Bong walks at 10kph for 0.3 hours, thats =
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