SOLUTION: This is a problem from the Jubilee Academy's online homeschooling website, which I am enrolled in. A freight train leaves a station traveling a constant speed of 30 miles per ho

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: This is a problem from the Jubilee Academy's online homeschooling website, which I am enrolled in. A freight train leaves a station traveling a constant speed of 30 miles per ho      Log On

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 Click here to see ALL problems on Travel Word Problems Question 198139: This is a problem from the Jubilee Academy's online homeschooling website, which I am enrolled in. A freight train leaves a station traveling a constant speed of 30 miles per hour (mph). A passenger train leaves at the same time and travels in the same direction at a constant speed of 35 mph. In how many hours will the trains be 15 miles apart? I would be able to do this problem easily if i knew how to set up the equation, which is for me the hardest part, but there were no similar solvers in the travel and distance section. Thank you.Answer by RAY100(1637)   (Show Source): You can put this solution on YOUR website!Remember that x = Vt,,, where x is distance, V is velocity, and t is time . delta x = V2t2 - V1t1 . but t1 = t2 . delta x = (v2-v1) t . 15 mi = ( 35 -30 ) mph * t . 15 = 5 t . t=3 hrs . check . V2 = 35 *3 = 105 miles . V1 = 30 * 3 = 90 . v2 -v1 =15 ok