# SOLUTION: Respected sir, 1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ? 2] Ritu goes to school at 10 kmph & reaches the s

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: Respected sir, 1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ? 2] Ritu goes to school at 10 kmph & reaches the s      Log On

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 Question 195410: Respected sir, 1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ? 2] Ritu goes to school at 10 kmph & reaches the school 6 minutes late.Nwxt day, she covers this distance at 12 kmper hour & reaches the school 9 minutes eariler than the scheduled time.what is the distance of her school from her house ? plz sir help me to solve this arith problem. waiting for yurs reply. take care thank u.Answer by ankor@dixie-net.com(15624)   (Show Source): You can put this solution on YOUR website!1] A distance is covered in 3 hours 48 min. at 5 kmph. how much time will be taken to cover it at 28.5 kmph ? : Convert 3 hr 48 min to hrs; 3 + 48/60 = 3.8 hrs : we can use inverted ratio here, (Time varies inversely to speed) let t = time to cover the dist at 28.5 km/hr = Cross multiply 28.5t = 5*3.8 : 28.5t = 19 t = t = hr to cover that dist at 28.5 km ; Check solution by finding the dist at each speed and time .67 * 28.5 ~ 19 km 3.8 * 5 = 19 km : : 2] Rita goes to school at 10 kmph & reaches the school 6 minutes late. Next day, she covers this distance at 12 km/hr & reaches the school 9 minutes earlier than the scheduled time. What is the distance of her school from her house? ; Let's just say the time difference between the two trips is 15 min, which hr Write a time equation Time = 12 km time + hr = 10 km time + = Multiply equation by 60 to get rid of the denominators, results: 5d + 15 = 6d : 15 = 6d - 5d d = 15 km is the distance ; ; Check solution by finding the time of each trip 15/10 = 1.5 hr 15/12 = 1.25 hr ---------------- differ= .25 hr which is 15 min