SOLUTION: Two cars start from the same point and ride in opposite directions. One car travels 30 mph slower than the other car. in six hours they are 600 miles apart. what is the rate of eac

Question 192971: Two cars start from the same point and ride in opposite directions. One car travels 30 mph slower than the other car. in six hours they are 600 miles apart. what is the rate of each car? D=rt
Found 2 solutions by RAY100, bhayzone:
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let rate of one car be x, rate of other is (x-30)
given t=6
given d=600 at t=6
d1 = x*6
d2 =(x-30)*6
D1+D2=600=x*6+(x-30)*6=6(2x-30)
divive both sides by 6
100=(2x-30)
add 30 both sides
130=2x
divide both sides by 2
65=x
(x-30)=35
checking
65-35=30 ok
(65 +35) 6=100*6=600 ok
Answer by bhayzone(8) (Show Source): You can put this solution on YOUR website!
Let,
r = rate of the slower driver.
r+30 = rate of faster driver.
In 6 hours,
Slower driver drives 6*r miles (dist = rate*time)
Faster driver drives 6*(r+30)
Totally between them they driver 600 miles.
Thus,
6*r + 6*(r+30)=600
Solving for r, we get
r (slover drivers rate) = 35 mph
r+30 (faster driver rate)= 65mph

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