# SOLUTION: A diesel train traveled to Johannesburg and back. It took 9 hours longer to go there than it did to come back. The average speed on the trip there was 10 km/h. The average speed o

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: A diesel train traveled to Johannesburg and back. It took 9 hours longer to go there than it did to come back. The average speed on the trip there was 10 km/h. The average speed o      Log On

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 Question 191682: A diesel train traveled to Johannesburg and back. It took 9 hours longer to go there than it did to come back. The average speed on the trip there was 10 km/h. The average speed on the way back was 55 km/h. How many hours did trip there take. ManishAnswer by ankor@dixie-net.com(15652)   (Show Source): You can put this solution on YOUR website! It took 9 hours longer to go there than it did to come back. The average speed on the trip there was 10 km/h. The average speed on the way back was 55 km/h. How many hours did trip there take. : Let t = time to come back then (t+9) = time to got there : The two trip were the same distance, write a distance equation from this fact: Dist = speed * time : to dist = from dist 10(t+9) = 55t 10t + 90 = 55t 90 = 55t - 10t 90 = 45t t = t = 2 hrs to return, and 11 hrs to go ; ; Check solution, find the distances 11*10 = 110 km 2*55 = 110 km