SOLUTION: Dave averaged 30 miles per hour on his bike trip to a friend's house. His return trip took an hour longer, as he averaged 20 miles per hour. What was his one-way distance to his

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: Dave averaged 30 miles per hour on his bike trip to a friend's house. His return trip took an hour longer, as he averaged 20 miles per hour. What was his one-way distance to his       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 190440: Dave averaged 30 miles per hour on his bike trip to a friend's house. His return trip took an hour longer, as he averaged 20 miles per hour. What was his one-way distance to his friends?
d = s * t
Answer by msaxby(1) About Me  (Show Source):
You can put this solution on YOUR website!
Let t = time to the friends house.
Since d = s *t, 30*t = distance to the friend's house.
and 20*(t+1) = the distance back from the friend's house.
SO: 30*t = 20*(t+1)
30*t = 20*t + 20
10*t = 20
t = 2 (hours).
Since Dave averaged 30 miles per hour, it is 30*2 miles to his friend's house or 60 miles.
(Check: Averaging 20 mph would take 60 / 20 or 3 hours - that's 1 hour longer.)