SOLUTION: Katy leaves City A for City B at 7 A.M., driving at 47 mi/h. At 9 A.M., Jensen leaves City B for City A, driving at 55 mi/h along the same route. If the cities are 298 mi apart, at

Question 188992: Katy leaves City A for City B at 7 A.M., driving at 47 mi/h. At 9 A.M., Jensen leaves City B for City A, driving at 55 mi/h along the same route. If the cities are 298 mi apart, at what time (A.M.) will they meet? [NOTE: Give the number of your answer only - do not label the answer.]
Answer by jonvaliente(64) (Show Source): You can put this solution on YOUR website!
At 9AM (2 hours after Kay left City A), Katy would have already traveled:
47*2=94 miles
That leaves a distance of:
298-94=204 miles left to City B
If we let x = no of hours that Katy and Jensen needs to travel to cover all 204 miles, then:

This gives us:

Dividing both sides by 102:

The answer is 2
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