Two trains traveling on parallel tracks are going toward each other from a distance of 960 kilometers. if one train moving at 100 kilometers per hour and the other is moving at 140 kilometers per hour, after how many hours will the trains pass each other?
Their approach rate is 100+140 or 240 km/h and 960/240 = 4 hours.
But here is the way to do it with algebra. Make this chart:
RATE TIME DISTANCE
Slower train
Faster train
Put in the rates and t for the time until they pass:
RATE TIME DISTANCE
Slower train 100 t
Faster train 140 t
Then use DISTANCE = RATE x TIME to fill in the distances
RATE TIME DISTANCE
Slower train 100 t 100t
Faster train 140 t 140t
The the sum of their distances traveled must equal the
960 km they were at the start, so the equation is
Slower train's distance traveled to point of passing
+
Faster train's distance to point of passing
=
960 km.
100t + 140t = 960
Solve that and get 4 hours.
Edwin