SOLUTION: A bicyclist biking on a straight road at a steady 12 mph is being chased by a dog running at 15 miles per hour. If the cyclist is 50 feet ahead of the dog and each continues at th

Question 186567: A bicyclist biking on a straight road at a steady 12 mph is being chased by a dog running at 15 miles per hour. If the cyclist is 50 feet ahead of the dog and each continues at the same rate, how long, to the nearest 10th of a minute, will it take the dog to catch up to the cyclist? (1 mile = 5,280 ft)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A bicyclist biking on a straight road at a steady 12 mph is being chased by a dog running at 15 miles per hour. If the cyclist is 50 feet ahead of the dog and each continues at the same rate, how long, to the nearest 10th of a minute, will it take the dog to catch up to the cyclist? (1 mile = 5,280 ft)
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The dog is gaining on the cyclist at 3 mph.
1 mph = 88 ft/min, so 3 mph = 264 ft/min
50/264 = 0.189393... minutes
--> 0.2 minutes
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