SOLUTION: Joseph live 5 miles from the school and Maya lives 2 miles from the school. If Joseph walks from his house in the opposite direction from the school at a speed of 4 miles an hour

Question 181446: Joseph live 5 miles from the school and Maya lives 2 miles from the school. If Joseph walks from his house in the opposite direction from the school at a speed of 4 miles an hour and Maya walks from her house in the opposite direction from the school at a speed of 6 miles per hour, after how long will they be the same distance from the school? What is the distance?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!

Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let t=time that elapses 'till they are the same distance from school
Distance Joseph is from school=5+4t
Distance Maya is from school=2+6t
The above two distances are the same, so:
Our equation to solve is:
5+4t=2+6t subtract 2 and also 4t from each side
5+4t-4t-2=2-2+6t-4t collect like terms
3=2t divide each side by 2
t=1.5 hr------------time that elapses 'till they are the same distance from school
Distance Joseph is from school=5+4*1.5 =11 mi
or
Distance Maya is from school=2+6*1.5=11 mi

Hope this helps----ptaylor

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