SOLUTION: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the ra
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Question 181114: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the rate of the faster squad? Found 2 solutions by ankor@dixie-net.com, josmiceli:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! two military squads are 26 miles apart. they plan to rendezvous at some
intermediate point. if one squad hikes 2/3 mph faster than the other,
and they meet in 3 hrs, what is the rate of the faster squad?
:
Let s = the speed of the faster squad
then
(s-) = speed of the slow-pokes
:
The total dist of both squads = 26 mi, they both travel for 3 hrs:
write a distance equation dist = time * speed
:
3s + 3(s-) = 26
Multiply what's inside the brackets
3s + 3s - 2 = 26
6s = 26 + 2
6s = 28
s =
s = 14/3 or 4 mph is the speed of the faster squad
:
:
check solution by finding the dist traveled by each (slower squad = 4 mph)
3 * 4 = 12
3 * = 14
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Total 26 mi
You can put this solution on YOUR website! Let = the rate of the slower squad
Let = the distance the slower squad travels in 3 hrs
given:
The rate of the faster squad is
The distance the faster squad travels in 3 hrs is
---------------------
For slower squad:
(1)
For faster squad:
(2)
Subtract (1) from (2)
(2)
(1) mi/hr
The rate of the faster squad is mi/hr
The faster squad's rate was 4.67 mi/hr
check answer mi mi/hr
OK