SOLUTION: In a cartoon , a malfunctioning cannon fires a hungry coyote towards the bottom of a cliff with an initial rate of 100 feet per second. If the cliff is 1250 feet tall, how long wil

Question 180178: In a cartoon , a malfunctioning cannon fires a hungry coyote towards the bottom of a cliff with an initial rate of 100 feet per second. If the cliff is 1250 feet tall, how long will it take the coyote to reach the desert floor? ( To account for gravity , use the formula d - rt + 16^2, where d = dustance, r = initiall rate, and t = time).
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a cartoon , a malfunctioning cannon fires a hungry coyote towards the bottom of a cliff with an initial rate of 100 feet per second. If the cliff is 1250 feet tall, how long will it take the coyote to reach the desert floor?
-------------------------
-16t^2-100t = -1250
16t^2 + 100t - 1250 = 0
(4t-25)(4t+50) = 0
Positive solution:
t = 25/4 = 6.25 seconds
===========================
Cheers,
Stan H.
RELATED QUESTIONS
In a cartoon , a malfunctioning cannon fires a hungry coyote towards the bottom of a... (answered by nerdybill)

in a cartoon, a malfunctioning cannon fires a hungry coyote towards the bottom of a cliff (answered by Alan3354)

I having trouble with this question because it is not following the regular D=r x t rule... (answered by stanbon)

A cannon ball is fired from a cliff that is 260 feet high with an initial speed of 128... (answered by josmiceli)

Wile E. Coyote is standing on a springboard atop a high cliff. Roadrunner drops a boulder (answered by josmiceli)

A cannon fires a cannonball as shown in the figure. The path of the cannonball is a... (answered by ankor@dixie-net.com)

the height in feet of an object shot from a cannon with initial velocity of 20 feet per... (answered by ankor@dixie-net.com)

1. If you take a car moving at constant velocity of 40 km/hr towards east for three hours (answered by KMST)

A cannon fires a cannonball whose path is a parabola with vertex at the highest point... (answered by josmiceli)