SOLUTION: Hi there, I don't get this problem with quadratic formulas! Could someone please help me work out this problem before class? 2t^3 -6t + 1 = 0 Thank you AC

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Question 17657: Hi there,
I don't get this problem with quadratic formulas! Could someone please help me work out this problem before class?
2t^3 -6t + 1 = 0
Thank you
AC

Answer by xcentaur(357)   (Show Source): You can put this solution on YOUR website!
2t^3 -6t + 1 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=28 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.8228756555323, 0.177124344467705. Here's your graph:



But if you're question is:
2t^3 -6t + 1 = 0
Then,
t(2t^2-6)=-1
then t=-1 or (2t^2-6)=-1


(2t^2-6)=-1
2t^2=-1+6
t^2=5/2



Then or


Hope this helps,
Prabhat

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