SOLUTION: Akram drove from Rochester to Albany, a distance of 219 miles. After the first 1.5 miles of travel, it started to snow and he reduced his speed by 26 miles per hour. It took him an

Question 175278: Akram drove from Rochester to Albany, a distance of 219 miles. After the first 1.5 miles of travel, it started to snow and he reduced his speed by 26 miles per hour. It took him another 3 hours to complete the trip. Express, in r terms, the distance that Akram traveled in the first part of the trip. then express the distance that Akram traveled in the second part of the trip. then find the speed at which Akram traveled for each part of the trip. please help. D
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I think you have a mistake in this problem (probably why no one responded)
" After the first 1.5 miles of travel" should be "after 1.5 hrs of travel"
Assuming that is the way it should be:
:
Akram drove from Rochester to Albany, a distance of 219 miles. After the first
1.5 hrs of travel, it started to snow and he reduced his speed by 26 miles
per hour. It took him another 3 hours to complete the trip.
Express, in r terms, the distance that Akram traveled in the first part of the trip.
r = initial speed. Dist = time * speed
:
d(r) = 1.5r
:
then express the distance that Akram traveled in the second part of the trip.
d(r) = 3(r-26)
then find the speed at which Akram traveled for each part of the trip
:
Write a distance equation:
intitial speed dist + 2nd part dist = 219 mi
1.5r + 3(r-26) = 219
:
1.5r + 3r - 78 = 219
:
4.5r = 219 + 78
:
4.5r = 297
r =
r = 66 mph on the 1st part of the trip
then
66 - 26 = 40 mph on the 2nd part of the trip
;
:
Check solution by adding the distances
1.5(66) + 3(40) =
99 + 120 = 219 mi, confirms our solutions
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