SOLUTION: a moving van leaves a house traveling at an average rate of 35 mi/h. the family leaves the house 3/4 hour later following the same route in a car. they travel at an average rate of
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Question 173668: a moving van leaves a house traveling at an average rate of 35 mi/h. the family leaves the house 3/4 hour later following the same route in a car. they travel at an average rate of 50 mi/h.
a.define a variable for the time traveled by the moving van.
b.write an expression for the time traveled by the car.
c. copy and complete the table.
vehicle rate time distance traveled
moving van x x x
car x x x
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
a) call the time traveled by the van t
b.) time traveled by car call which equals t-3/4
c)
:
........rate........time.......distance
van......35...........t.........35t
car......50..........t-3/4......50t-75/2
:
so for
.................................van mi...........car mi
D(t)=D(1/2)............35/2.........0(they hadnt started driving yet)
.....D(1)......................35...........25/2
.....D(3/2).................105/2..........75/2
.....D(2).....................70..............125/2
.....D.............175/2.......175/2(at this point they are at the same spot)
:
if you were doing this by formulas
:
D=35t and D=50t-75/2...since the Distances are equal when the car catches up, this allows us to set the equations equal to one another.
:
35t=50t-75/2..multiply each term by 2
:
70t=100t-75
:
-30t=-75
:
t=-75/-30=75/30=25/10=
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