SOLUTION: Two cars leave their respective towns ,wich are 1000 km appart, travelind towards each other. One cars leavesat 8 am and average 120km/h . The other car leaves at 9am and averages

Question 171787: Two cars leave their respective towns ,wich are 1000 km appart, travelind towards each other. One cars leavesat 8 am and average 120km/h . The other car leaves at 9am and averages 100km/h. When and where will they meet each other? At what time will they be 500 kilometers apart?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two cars leave their respective towns, which are 1000 km apart, traveling
towards each other. One cars leave sat 8 am and average 120km/h.
The other car leaves at 9am and averages 100km/h.
:
When and where will they meet each other?
:
Let t = travel time of the 1st car
then
(t-1) = travel time of the 2nd car
:
When they do meet, they will have traveled a total distance of 1000 km
Write a distance equation from this fact: Dist = speed * time
:
1st car dist + 2nd car dist = 1000 km
120t + 100(t-1) = 1000
120t + 100t - 100 = 1000
120t + 100t = 1000 + 100
220t = 1100
t =
t = 5 hrs which will be 1 pm when they will meet
:
They will meet at 5*120 = 600 km from car 1's starting point
or
4 * 100 = 400 km from car 2's starting point (for a total 1000 km)
:
:
:
At what time will they be 500 kilometers apart?
:
They will have traveled half way, use the same equation to find t:
120t + 100(t-1) = 500
120t + 100t - 100 = 500
120t + 100t = 500 + 100
220t = 600
t =
t = 2.72 hrs or 2 hrs 43.6 min which is 10:44
:
:
Check this
2.73 * 120 = 328.0 km from car A starting point
1.72 * 100 = 172.0 km from car B starting point
-------------------
total driven 499.6 km ~ 500
:
A.............328>.....................<172.......B (1000)
1000 - 328 - 172 = 500 km
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