# SOLUTION: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twic

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 Question 171054: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane. ----------------- Their combined rates = 4500 miles/5 hrs = 900 mph ---------------- EQUATION: Their rates are 2x and x 2x+x = 900 3x = 900 x = 300 mph (rate of slow plane) 2x = 600 mph (rate of fast plane) ====================================== Cheers, Stan H.