SOLUTION: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twic
Algebra.Com
Question 171054: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.
-----------------
Their combined rates = 4500 miles/5 hrs = 900 mph
----------------
EQUATION:
Their rates are 2x and x
2x+x = 900
3x = 900
x = 300 mph (rate of slow plane)
2x = 600 mph (rate of fast plane)
======================================
Cheers,
Stan H.
RELATED QUESTIONS
Two planes left at the same time from two airports that are 1550 miles apart and flew... (answered by ankor@dixie-net.com)
two planes left at the same time from two airports that are 1550 miles apart and flew... (answered by ikleyn)
Two planes left at the same time from two airports which are 4500 miles apart and flew... (answered by stanbon)
Two planes left at the same time for two airports that are 3600 miles apart and flew... (answered by anand429)
Two planes started at the same time from two airports that are 3,600 kilometers apart and (answered by fdsalicia)
Two planes started at the same time from tow different airports that are 3,600 kilometers (answered by checkley77,stanbon)
Two planes left at the same time from airports 4500 miles apart and flew toward each... (answered by lwsshak3)
Two planes started at the same time from the same airport and flew in opposite... (answered by whty89,Paul)