You can
put this solution on YOUR website!distance equals rate times time
lets call the 1st 150 miles rate=r and time=t
and we will call the last 100 miles rate r-5 and time 10-t
:
150=rt--->t=150/r.....eq 1
100=(r-5)(10-t).......eq 2
:
take value of t from eq 1 and plug it into eq 2
:
100=(r-5)(10-(150/r))--->100=(r-5)((10r-150)/r)...multiply both sides by r
:
100r=(r-5)(10r-150)
:
divide by 10
:
r=27.25 and 2.75......throw out the 2.75 rate because r-5 is negative.
so
mph-the original speed of the storm
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=600 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 27.2474487139159, 2.75255128608411.
Here's your graph:
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