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put this solution on YOUR website!d=r*t
distance going =distance returning=350
:
so r*t going = r*t returning
:
rt=(r+10)(t-4)
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rt=rt-4r+10t-40-----> we have -4r+10t-40=0 since t=350/r
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we have -4r+10(350/r)-40=0
:
-4r+(3500/r)-40=0---->mult by r--->


:
quadratic formula yields 25 and -35...we throw out the negative value
:
r=25 going
r+10=35 returning
:
time going

hours
time returning

hours