SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
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Question 166415: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist
travels at 10 miles per hour and starts 3 hours after the first cyclist who is
traveling at 6 miles per hour. How much time will pass before the second cyclist
catches up with the first from the time the second cyclist started biking?
:
Let t = travel time of the 2nd cyclist (10 mph)
then
(t+3) = travel time of the 1st cyclist (6 mph)
:
When the 2nd cyclist catches up with the 1st they will have traveled the same distance
:
Write a distance equation using this fact: (Dist = speed * time)
:
10s = 6(s+3)
:
10s = 6s + 18
:
10s - 6s = 18
:
4s = 18
s =
s = 4.5 hrs travel time of the 2nd cyclist
:
;
Check solution by confirming they traveled the same distance
7.5 * 6 = 45 mi
4.5 * 10 = 45 mi
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