SOLUTION: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Algebra.Com
Question 166413: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
rate times time = distance.
rate = R
time = T
distance = D
-----
R*T = D
T = 30 minutes = 1/w hour
D = 28 miles
R*(1/2) = 28
R = 2*28
R = 56
-----
he will have to travel at 56 miles per hour.
RELATED QUESTIONS
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by AnlytcPhil)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by fractalier)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by tutorcecilia)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30... (answered by checkley71)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by stanbon)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by stanbon)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30... (answered by chitra)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by rfer)
John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. (answered by richwmiller)