SOLUTION: at 7 am two cars started from the same place, one traveling east and the oher traveling west. at 10:30 am they were 287 miles apar. if the rate of the fast car exceeded the rate of

Question 165963: at 7 am two cars started from the same place, one traveling east and the oher traveling west. at 10:30 am they were 287 miles apar. if the rate of the fast car exceeded the rate of the slow car by 6 mph, find the rate of each car.
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

Remember: ;
In the condition: FC exceeded SC by 6mph ---> , EQN 1
We know that and that covered 287 miles in 3.5 hours (10:30-7:00=3.5 hrs) right?
.
Putting into eqn all given via our formula:
, plug in EQN 1:

, cross multiply
---->

, Speed of Slow Car
Via EQN 1,
, Speed of Fast Car
In doubt? Both cars should travlled a Distance of 287 miles in 3.5 hrs. Let's see,

Thank you,
Jojo

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