SOLUTION: two trains started from the same place at the same time and traveled in opposite directions. after traveling 10 hours, they were 850 miles apart. the rate of the fast train exceede

Algebra.Com
Question 165945: two trains started from the same place at the same time and traveled in opposite directions. after traveling 10 hours, they were 850 miles apart. the rate of the fast train exceeded the rate of the slow train by 5 mph. find the rate of each train.
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
10X+10(X+5)=850
10X+10X+50=850
20X=850-50
20X=800
X=800/20
X=40 MPH FOR THE SLOWER TRAIN.
40+5=45 MPH FOR THE FASTER TRAIN.
PROOF:
10*40+10*45=850
400+450=850
850=850

RELATED QUESTIONS

two trains started from the same place at the same time and traveled in opposite... (answered by oscargut)
Two trains started from the same station at the same time and traveled in opposite... (answered by JulietG)
two trains started from the same station at the same time and traveled in opposite... (answered by josgarithmetic)
Two trains started fromt he same station at the same time and traveled in opposite... (answered by nerdybill)
two trains started at the same time from the same station and traveled opposite... (answered by Alan3354)
Two trains started from the same place at the same time and traveled in opposite... (answered by venugopalramana)
Two trucks leave the same place at the same time, traveling in opposite directions. One... (answered by josmiceli)
Two trains leave the station at the same time going in opposite directions. One of the... (answered by checkley79)