SOLUTION: At 1:30pm Tom leaves in his boat from a dock and heads south at a rate of 25 miles per hour. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If s

Question 165431: At 1:30pm Tom leaves in his boat from a dock and heads south at a rate of 25 miles per hour. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour, when will she catch up to Tom? Write an equation to find the value for Toms Time.
Answer by alicealc(293) (Show Source): You can put this solution on YOUR website!
Tom's speed = 25 mph
Mary's speed = 30 mph

Let Tom's time = t hours
so, Mary's time = (t - (10/60)) hours

when Mary and Tom meets:
Mary's distance = Tom's distance
30*(t - 1/6) = 25*t
<=> 30t - 5 = 25t
<=> 30t - 25t = 5
<=> 5t = 5
<=> t = 5/5 = 1

so, Mary can catch Tom 1 hour after Tom left,
that means, she can catch Tom at 2:30pm
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