SOLUTION: A man travels for work averaging 40 mph.On the return trip he averages 50 mph, and it takes him an hour less time. How long was the return trip?
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Question 164878: A man travels for work averaging 40 mph.On the return trip he averages 50 mph, and it takes him an hour less time. How long was the return trip?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=40T
D=50(T-1)
40T=50(T-1)
40T=50T-50
-10T=-50
T=-50/-10
T=5 HOURS.
PROOF:
D=40*5=200 MILES.
D=50(5-1)=50*4=200 MILES.
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