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put this solution on YOUR website!An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50
miles away. The express travels twice as fast as the local, and arrives 1 hour
ahead of it. Find the speed of each train.
:
Let s = local train speed
then
2s = express train speed
:
Write a time equation: Time =

:
Freight time = Express time + 1 hr

=

+ 1
Multiply equation by 2s to get rid of the denominators
2(50) = 50 + 2s
100 - 50 = 2s
:
s =

s = 25 mph is the freight speed, obviously 50 mph is the express speed
:
:
Check solution by find the time of each
50/25 = 2 hr
50/50 = 1 hr, (1 hr less than the freight