SOLUTION: If a pro basketball player has a vertical leap of about 25 inches, what is his hang time? Use the hang-time formula V=48 T^2

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Question 162665: If a pro basketball player has a vertical leap of about 25 inches, what is his hang time? Use the hang-time formula V=48 T^2
Answer by josmiceli(6785) About Me  (Show Source):
You can put this solution on YOUR website!
25+=+48t%5E2
Divide both sides by 48
t%5E2+=+25%2F48
Take the square root of both sides
t+=+.722sec
the hang time is .722 sec
Now check answer
25+=+48%2A.722%5E2
25+=+48%2A.521
25+=+25.02close enough