SOLUTION: A MAN ROWED 10 KM UP A RIVER IN 5 HOURS AND BACK IN 21 AND A HALF HOURS. FIND THE RATE OF THE CURRENT AND HIS RATE OF ROWING IN STILL WATER.

Question 162663: A MAN ROWED 10 KM UP A RIVER IN 5 HOURS AND BACK IN 21 AND A HALF HOURS. FIND THE RATE OF THE CURRENT AND HIS RATE OF ROWING IN STILL WATER.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let his rate in still water =
Let the rate of the current =
His rate against the current is
His rate with the current is
The distance both ways is km
distance = rate * time
(1) mi (with the current)
(2) mi (against the current)
----------------------------------------------------
(1)
(2)
Multiply both sides of (2) by
(2)
Multiply both sides of (1) by
(1)
(2) Now add the equations
(3)
km/hr
(1)

km/hr
His rate in still water is 1.233 km/hr
The rate of the current is .7674 km/hr
check answer:
(1)
(2)
--------------------------
(1)

error due to rounding off
(2)

(error due to rounding)
OK
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