SOLUTION: At noon Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 mph. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If

Question 161625: At noon Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 mph. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour at what time will she catch up with Tom?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
25T=30(T-1/6)
25T=30T-5
25T-30T=-5
-5T=-5
T=1 HOUR IS THE CATCH-UP TIME FOR MARY.
PROOF:
25*1=30(1-1/6)
25=30*5/6
25=150/6
25=25 MILES IS THE DISTANCE TRAVELED BEFORE THE CATCH-UP.
RELATED QUESTIONS
i cant figure out how to put this in a algebra equation. "At 1:30p.m., Tom leaves in his... (answered by richwmiller)

At 1:30pm Tom leaves in his boat from a dock and heads south at a rate of 25 miles per... (answered by alicealc)

At 1:30 pm, Tom leaves in his boat from a dock and heads south. He travels at a rate 0f... (answered by ankor@dixie-net.com)

Michael Chan leaves a dock in his motorboat and travels at an average speed of 9 mph... (answered by josmiceli)

�Michael Chan leaves a dock in his motorboat and travels at an average speed of 9 mph... (answered by Boreal)

Michael Chan leaves a dock in his motorboat and travels at an average speed of 9 mph... (answered by Theo,MathTherapy,greenestamps)

A boat leaves a dock and travels at a rate of 36 kilometers per hour. Twenty minutes... (answered by scott8148)

A boat leaves a dock and travels at the rate of 36 kilometers per hour. Twenty minutes... (answered by greenestamps)

if a car leaves at a speed of 25 mph and travels ten minutes then another car leaves from (answered by kevwill)