SOLUTION: Joe left Southlake on his bicycle riding at an average rate of 8 miles per hour...five hours before his father left by automobile. The father overtook JOe in exactly one hour. At w

Question 159120: Joe left Southlake on his bicycle riding at an average rate of 8 miles per hour...five hours before his father left by automobile. The father overtook JOe in exactly one hour. At what average rate was Joe's father traveling?
(Need to define a variable, write an equation, and solve)
TRIED:
variable: x=father's mph
equation: x=8mph(6hrs)
solve: x=48 mph
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Joe left Southlake on his bicycle riding at an average rate of 8 miles per hour. Five hours before his father left by automobile. The father overtook Joe in
exactly one hour. At what average rate was Joe's father traveling?
:
Let s = Father's speed
:
Travel time for Joe = 5 + 1 = 6 hrs
Travel time for Father = 1 hr
:
When Father overtakes Joe, they will have traveled the same distance.
Write a distance equation from this fact; dist = time * speed
:
Father's dist = Joe's dist
1s = 6 * 8
s = 48, just like you said

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