SOLUTION: Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours Kayla finally caught

Question 158676: Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours Kayla finally caught up. Find Jose's average speed.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours Kayla finally caught up. Find Jose's average speed.
:
Let s = J's speed
then
(s+35) = k's speed
:
K's travel time: 1.2 hrs
J's travel time: 2.1 + 1.2 = 3.3 hrs
:
When K catches up with J, they will have traveled the same distance
Write a distance equation from this fact: Dist = time * speed
:
J's dist = K's dist
3.3s = 1.2(s+35)
3.3s = 1.2s + 42
3.3s - 1.2s = 42
2.1s = 42
s =
s = 20 mph is J's speed
:
:
Check solution by finding that the distance each traveled is equal
K's speed = 20 + 35 = 55 mph
1.2 * 55 = 66 mi
and J's dist:
3.3 * 20 = 66 mi
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