SOLUTION: A bullet if fired horizontally at a target, and the sound of its impact is heard 1.5 seconds later. If the speed of the bullet is 3300ft/sec and the speed of sound is 1100ft/sec, h
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Question 158515: A bullet if fired horizontally at a target, and the sound of its impact is heard 1.5 seconds later. If the speed of the bullet is 3300ft/sec and the speed of sound is 1100ft/sec, how far away is the target?
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Remember: ----> , working eqn
AMP Parsing Error of [Speed[b]=S[b]=3300(ft/sec)]: Invalid function ')': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
.
AMP Parsing Error of [Speed[s]=S[s]=1100(ft/sec)]: Invalid function ')': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
.
Note: in question?
In our working eqn, we get:
, where ,---> why?
When the target was hit, sound travelled back 1.5 sec later. It does not mean you hit the target in 1.5 sec, you hit earlier than that. We need to subtract the speed of sound for that matter. Continuing:
AMP Parsing Error of [S=(3300-1100)(ft/sec)=2200(ft/sec)]: Invalid function ')=2200(ft/sec)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
.
Then,
AMP Parsing Error of [d=(2200(ft/cross(sec)))(1.5cross(sec))]: Invalid function ')))(1.5\cross(sec))': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70.
.
---------------------> total distance of the target
Thank you,
Jojo
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