You can
put this solution on YOUR website!Let
-----------------> faster car
---------------------> slower car
Remember the situation, that
is ahead of
at a certain
that we're looking for. Putting that into equation, we need to add
to
to cover the gap of
:
, cross multiply
, divide both side by 15 to solve "time":
---> time=3 hours & 20mins
After
and
,
will be 50 miles ahead of
. In doubt? Let' see:
DISTANCE OF
AFTER 3 hours & 20 minutes:
DISTANCE OF
AFTER 3 hours & 20 minutes:
Thank you,
Jojo
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