# SOLUTION: A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly the 300 miles when flying against the wind. What is the plane's speed in still air?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly the 300 miles when flying against the wind. What is the plane's speed in still air?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Travel Word Problems Question 155941: A plane flies 300 miles with a tail wind in 1 hour. It takes the same plane 2 hours to fly the 300 miles when flying against the wind. What is the plane's speed in still air?Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r Let r=rate(speed) of plane in still air Let r1=rate (speed) of tailwind With tailwind: 300=(r+r1)*1 300=r+r1-------------------------------eq1 Against tailwind: 300=(r-r1)*2 300=2r-2r1------------------------------eq2 multiply eq1 by 2 and then add it to eq2: 600=2r+2r1----------eq1a 300=2r-2r1-------------eq2 900=4r divide each side by 4 r=225 mph---------------------------speed of plane in still air substitute r=225 mph into eq1 300=225+r1 subtract 225 from each side 300-225=225-225+r1 collect like terms 75=r1 or r1=75 mph----------------------speed of wind CK 300=(225+75)*1 300=300 and 300=(225-75)*2 300=150*2 300=300 Hope this helps--ptaylor