SOLUTION: Can you please help me with this word problem: At 7:00 am Joe starts jogging at 6mi/h. At 7:10 am Ken starts off after him. HOw fast must Ken run in order to overtake him at 7:30 a
Algebra.Com
Question 155764: Can you please help me with this word problem: At 7:00 am Joe starts jogging at 6mi/h. At 7:10 am Ken starts off after him. HOw fast must Ken run in order to overtake him at 7:30 am?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
6*.5=20/60*x
3=20x/60
20x=3*60
20x=180
x=180/20
x=9 mph is Ken's speed.
RELATED QUESTIONS
at 7:00 am joe starts jogging at 6mi/h . At 7:10 Ken starts off after him. How fast must... (answered by lwsshak3,mananth)
At 7:00 A.M. Joe starts jogging at 6mi/h. At 7:10 A.M. Ken starts off after him. How fast (answered by College Student)
At 7 am Joe starts jogging at 6mi/hr. At 7:10 am Ken starts off after him. How fast... (answered by mananth)
at 7:00 AM joe starts jogging at 6 mi/h. at 7:10 am ken starts off after him. how fast... (answered by Alan3354)
I have been struggling on this math problem for a while now and I was wondering if anyone (answered by solver91311)
at 7:00a.m. Joe starts jogging at 6mi/h. At 7:10a.m. Ken starts off after him. How fast... (answered by Alan3354)
at 7:00 a.m joe starts jogging at 6 mi/h. at 7:30 ken starts off after him. how fast must (answered by richwmiller,ankor@dixie-net.com)
At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast (answered by ankor@dixie-net.com)
At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How... (answered by ankor@dixie-net.com)