SOLUTION: Mr. Newton drive to and from work over the same route each day. On Friday, he drives at an average rate of 52 mph/km and is one minute late to work. On Monday, he drives at an aver

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Question 153779: Mr. Newton drive to and from work over the same route each day. On Friday, he drives at an average rate of 52 mph/km and is one minute late to work. On Monday, he drives at an average rate of 60 mph/km and is one minute early to work. If he left home at the same time each day, what is the distance Mr. Newton travels one way to work?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Mr. Newton drive to and from work over the same route each day. On Friday, he drives at an average rate of 52 mph/km and is one minute late to work. On Monday, he drives at an average rate of 60 mph/km and is one minute early to work. If he left home at the same time each day, what is the distance Mr. Newton travels one way to work?
:
First find the times it takes him to get to work, then find the distance from that
:
Let t = time required if he arrives on time (in hrs)
then
(t+1%2F60) = time if he 1 min late
and
(t-1%2F60) = time if he 1 min early
;
Write a distance equation: Dist = speed * time
:
Monday dist = Friday dist
60(t-1%2F60) = 52(t+1%2F60)
:
60t-60%2F60 = 52t+52%2F60
:
60t - 52t = 60%2F60 + 52%2F60
:
8t = 112%2F60 hrs
we can get rid of that denominator (60); convert it to minutes, (mult by 60)
8t = 112
t = 112%2F8
t = 14 minutes for him to arrive on time
:
then we can say
It takes 13 min when he is 1 min early
and
15 min when he is 1 min late
:
:
Find the distances
52 * 15%2F60 = 13 miles
60 * 13%2F60 = 13 miles
;
Did this make sense?