SOLUTION: I need help with this question: mr. kasberg rides his bike at 6 mph to the bus station. he then rides the bus to work, averaging 30 mph. if he spends 20 minuts less time on th

Question 152378: I need help with this question:

mr. kasberg rides his bike at 6 mph to the bus station. he then rides the bus to work, averaging 30 mph. if he spends 20 minuts less time on the bus than on the bike, and the distance from his house to work is 26 miles, what is the distance from his house to the bus station?
i don't get how to solve this using an equation.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
kasberg rides his bike at 6 mph to the bus station. he then rides the bus to work, averaging 30 mph. if he spends 20 minutes less time on the bus than on the bike, and the distance from his house to work is 26 miles, what is the distance from his house to the bus station?
:
Convert 20 min to hrs: 20/60 = 1/3 hr
:
Let t = time on the bike
then
t-(1/3) = time on the bus
:
Write a dist equation Dist = speed * time:
:
Bike dist + bus dist = 26 mi
6t + 30[t-(1/3)] = 26
:
6t + 30t - 10 = 26
36t = 26 + 10
36t = 36
t = 1 hr on the bike
:
6 mph for 1 h = 6 mi from house to the bus station
:
:
Check solution by finding the distance
6(1) + 30(2/3) =
6 + 20 = 26 mi
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