SOLUTION: Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 6

Question 151754: Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63km/h, what time did Juan's brother overtake him?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63km/h, what time did Juan's brother overtake him?
.
You will need to apply the "distance" formula:
d = rt
where
d is distance
r is rate or speed
t is time
.
Let x = amount of time Juan's brother took to overtake him
.
x+2 = time Juan was on his bicycle
.
"distance traveled by Juan" = "distance traveled by Juan's brother"
.
21(x+2) = 63x
21x + 42 = 63x
42 = 42x
1 hour = x
.
Therefore, Juan's brother overtook him 1 hour after starting. And, since he started at noon, Juan's brother will overtake him at 1 PM.
.
Answer: 1 PM
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