SOLUTION: Mary Beth and Michael leave school traveling in opposite directions. Michael is walking and Mary Beth is biking, averaging 6km/h more than Michael. If they are 18km apart after 1

Question 151753: Mary Beth and Michael leave school traveling in opposite directions. Michael is walking and Mary Beth is biking, averaging 6km/h more than Michael. If they are 18km apart after 1.5 hours, what is Michael's rate?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Mary Beth and Michael leave school traveling in opposite directions. Michael is walking and Mary Beth is biking, averaging 6 km/h more than Michael. If they are 18 km apart after 1.5 hours, what is Michael's rate?
:
Let s = Michael's rate walking
Then
(s+6) = Mary's rate riding
;
Write a distance equation: Dist = time * speed
:
M's dist + M.B's dist = 18
1.5s + 1.5(s+6) = 18
1.5s + 1.5s + 9 = 18
3s = 18 - 9
s =
s = 3 km/hr is Micheal's walking rate
;
:
Check solution (9 km/hr is M.B.'s rate)
1.5(3) + 1.5(9) =
4.5 + 13.5 = 18
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